Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.7 - Addition and Subtraction of Fractions - Exercise: 20

Answer

$\frac{43}{48}$

Work Step by Step

Find the LCD. $\ \ \ \ \ 16=2\times2\times2\times2$ $\ \ \ \ \ 8\ \ =2\times2\times2$ $\ \ \ \ \ 3\ \ =\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3$ $\ \ \ \ \ 4\ \ =2\times2$ $LCD=2\times2\times2\times2\times3=48$ $\frac{3}{16}+\frac{1}{8}+\frac{1}{3}+\frac{1}{4}=\frac{3\times3}{16\times3}+\frac{1\times6}{8\times6}+\frac{1\times16}{3\times16}+\frac{1\times12}{4\times12}=\frac{9}{48}+\frac{6}{48}+\frac{16}{48}+\frac{12}{48}=\frac{9+6+16+12}{48}=\frac{43}{48}$
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