Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.7 - Addition and Subtraction of Fractions - Exercise: 19

Answer

$\frac{37}{48}$

Work Step by Step

Find the LCD. $\ \ \ \ \ 3\ \ =3$ $\ \ \ \ \ 6\ \ =3\times2$ $\ \ \ \ \ 16=\ \ \ \ \ \ \ 2\times2\times2\times2$ $\ \ \ \ \ 12=3\times2\times2$ $LCD=3\times2\times2\times2\times2=48$ $\frac{1}{3}+\frac{1}{6}+\frac{3}{16}+\frac{1}{12}=\frac{1\times16}{3\times16}+\frac{1\times8}{6\times8}+\frac{3\times3}{16\times3}+\frac{1\times4}{12\times4}=\frac{16}{48}+\frac{8}{48}+\frac{9}{48}+\frac{4}{48}=\frac{16+8+9+4}{48}=\frac{37}{48}$
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