Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.7 - Addition and Subtraction of Fractions - Exercise - Page 40: 45

Answer

$9\displaystyle \frac{13}{24}$

Work Step by Step

We combine the fractions by finding the LCD and simplify if necessary. We convert $16\frac{15}{24}$ to $15\frac{39}{24}$ to avoid negatives with mixed fractions. $16\displaystyle \frac{5}{8}-4\frac{7}{12}-2\frac{1}{2} =16\displaystyle \frac{15}{24}-4\frac{14}{24}-2\frac{12}{24} =15\displaystyle \frac{39}{24}-4\frac{14}{24}-2\frac{12}{24} =9\displaystyle \frac{13}{24}$
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