Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.7 - Addition and Subtraction of Fractions - Exercise: 46

Answer

$11\displaystyle \frac{31}{48}$

Work Step by Step

We combine the fractions by finding the LCD and simplify if necessary: $12\displaystyle \frac{9}{16}-3\frac{1}{6}+2\frac{1}{4}=12\displaystyle \frac{27}{48}-3\frac{8}{48}+2\frac{12}{48} =9\displaystyle \frac{19}{48}+2\frac{12}{48}=11\displaystyle \frac{31}{48}$
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