Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 9 - Section 9.1 - Solving Quadratic Equations by the Square Root Property - Exercise Set: 60

Answer

$x=\{3,11\}$

Work Step by Step

"The difference between a number and 7" is written as $x-7$. The equation can be written as: $(x-7)^2=16$ Take the square root of each side. $\sqrt{(x-7)^2}=\sqrt{16}$ Simplify. $x-7=\pm4$ Add 7 to each side. $x-7+7=\pm4+7$ Simplify $x=4+7$ or $x=-4+7$ $x=11$ or $x=3$ State as a solution set. $x=\{3,11\}$
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