Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 9 - Section 9.1 - Solving Quadratic Equations by the Square Root Property - Exercise Set: 54

Answer

$d\approx 6.32 \text{ units} $

Work Step by Step

Using $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ or the Distance Formula, then the distance, $d$, between the given points $( -4,-1 )$ and $( 2,-3 )$ is \begin{array}{l}\require{cancel} d=\sqrt{(-4-2)^2+(-1-(-3))^2} \\\\ d=\sqrt{(-6)^2+(2)^2} \\\\ d=\sqrt{36+4} \\\\ d=\sqrt{40} \\\\ d=\sqrt{4\cdot10} \\\\ d=\sqrt{(2)^2\cdot10} \\\\ d=2\sqrt{10} \\\\ d\approx 6.32 \text{ units} .\end{array}
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