Answer
$d\approx 6.32
\text{ units}
$
Work Step by Step
Using $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ or the Distance Formula, then the distance, $d$, between the given points $(
-4,-1
)$ and $(
2,-3
)$ is
\begin{array}{l}\require{cancel}
d=\sqrt{(-4-2)^2+(-1-(-3))^2}
\\\\
d=\sqrt{(-6)^2+(2)^2}
\\\\
d=\sqrt{36+4}
\\\\
d=\sqrt{40}
\\\\
d=\sqrt{4\cdot10}
\\\\
d=\sqrt{(2)^2\cdot10}
\\\\
d=2\sqrt{10}
\\\\
d\approx 6.32
\text{ units}
.\end{array}