Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 9 - Section 9.1 - Solving Quadratic Equations by the Square Root Property - Exercise Set - Page 632: 57


$d=16 \text{ units} $

Work Step by Step

Using $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ or the Distance Formula, then the distance, $d$, between the given points $( -2\sqrt{7},10 )$ and $( 4\sqrt{7},8 )$ is \begin{array}{l}\require{cancel} d=\sqrt{(-2\sqrt{7}-4\sqrt{7})^2+(10-8)^2} \\\\ d=\sqrt{(-6\sqrt{7})^2+(2)^2} \\\\ d=\sqrt{36\cdot7+4} \\\\ d=\sqrt{252+4} \\\\ d=\sqrt{256} \\\\ d=\sqrt{(16)^2} \\\\ d=16 \text{ units} .\end{array}
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