Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 9 - Section 9.1 - Solving Quadratic Equations by the Square Root Property - Exercise Set: 56

Answer

$d\approx 6.40 \text{ units} $

Work Step by Step

Using $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ or the Distance Formula, then the distance, $d$, between the given points $( -8,-4 )$ and $( -3,-8 )$ is \begin{array}{l}\require{cancel} d=\sqrt{(-8-(-3))^2+(-4-(-8))^2} \\\\ d=\sqrt{(-8+3)^2+(-4+8)^2} \\\\ d=\sqrt{(-5)^2+(4)^2} \\\\ d=\sqrt{25+16} \\\\ d=\sqrt{41} \\\\ d\approx 6.40 \text{ units} .\end{array}
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