Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 9 - Section 9.1 - Solving Quadratic Equations by the Square Root Property - Exercise Set: 48

Answer

$b=\sqrt{195} \text{ } m$

Work Step by Step

Using $a^2+b^2=c^2$ or the Pythagorean Theorem, then, \begin{array}{l}\require{cancel} 17^2+b^2=22^2 \\\\ 289+b^2=484 \\\\ b^2=484-289 \\\\ b^2=195 \\\\ b=\pm\sqrt{195} .\end{array} Since there are no negative measurements, then $ b=\sqrt{195} \text{ } m .$
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