Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.4 - Factoring Special Forms - Exercise Set: 85

Answer

$(3x+2)(9x^2-6x+4)$

Work Step by Step

The given binomial can be written as: $(3x)^3+2^3$ The binomial above is a sum of two cubes. RECALL: A sum of two cubes can be factored using the formula: $a^3+b^3=(a+b)(a^2-ab+b^2)$ Use the formula above to factor the sum of two cubes with $a=3x$ and $b=2$ to obtain: $=(3x+2)[(3x)^2-(3x)(2) + 2^2] \\=(3x+2)(9x^2-6x+4)$
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