# Chapter 6 - Section 6.4 - Factoring Special Forms - Exercise Set: 79

$(x+1)(x^2-x+1)$

#### Work Step by Step

The given binomial can be written as: $x^3+1^3$ The binomial aove is a sum of two cubes. RECALL: A sum of two cubes can be factored using the formula: $a^3+b^3=(a+b)(a^2-ab+b^2)$ Use the formula above to factor the sum of two cubes with $a=x$ and $b=1$ to obtain: $=(x+1)(x^2-x(1) + 1^2) \\=(x+1)(x^2-x+1)$

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