## Introductory Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 6 - Section 6.4 - Factoring Special Forms - Exercise Set - Page 454: 54

#### Answer

$(3x+1)^2$

#### Work Step by Step

RECALL: A perfect square trinomial can be factored using either of the following formulas: (i) $a^2+2ab+b^2= (a+b)^2$ (ii) $a^2-2ab+b^2=(a-b)^2$ The given perfect square trinomial can be written as: $=(3x)^2+2(3x)(1) + 1^2$ This trinomial has the same form as the perfect square trinomial in formula (i) above. Factor using formula (i) with $a=3x$ and $b=1$ to obtain: $=(3x+1)^2$

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