## Introductory Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 6 - Section 6.4 - Factoring Special Forms - Exercise Set: 18

#### Answer

$(x^5-1)(x^5+1)$

#### Work Step by Step

RECALL: A difference of two square can be factored using the formula $a^2-b^2=(a-b)(a+b)$ The given binomial can be written as: $=(x^5)^2-1^2$ The binomial above is a difference of two squares. Factor the difference of two squares using the formula above with $a=x^5$ and $b=1$ to obtain: $=(x^5-1)(x^5+1)$

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