Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.4 - Factoring Special Forms - Exercise Set: 28

Answer

$5(x-3)(x+3)$

Work Step by Step

Factor out $5$ to obtain: $=5(x^2-9)$ Write 9 as $3^2$ to obtain: $=5(x^2-3^2)$ The binomial factor above is a difference of two squares. RECALL: A difference of two square can be factored using the formula $a^2-b^2=(a-b)(a+b)$ Factor the difference of two squares using the formula above with $a=x$ and $b=3$ to obtain: $=5(x-3)(x+3)$
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