## Introductory Algebra for College Students (7th Edition)

Divide each term in the polynomial by the monomial. Subtract the powers of the variables to simplify each term. (16y$^2$-8y)$\div$y=$\frac{16y^2}{y}$-$\frac{8y}{y}$=16y$^{(2-1)}$-8(1)=16y-8 Check the answer. y(16y-8)=16y(y)-8(y)=16y$^2$-8y