Answer
$-\frac{1}{2}x^{12}$
Work Step by Step
Divide the monomials by cancelling out common factors of the numbers and subtracting the exponents of variables.
$\frac{-18x^{14}y^2}{36x^2y^2}=-\frac{18}{36}x^{(14-2)}y^{(2-2)}=-\frac{1}{2}x^{12}y^0=-\frac{1}{2}x^{12}$
Check the answer:
$36x^2y^2(-\frac{1}{2}x^{12})=-\frac{36}{2}x^{(2+12)}y^2=-18x^{14}y^2$
