Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.5 - Dividing Polynomials - Exercise Set: 29

Answer

$\dfrac{4x^6}{25}$

Work Step by Step

RECALL: (i) $\left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}, b\ne0$ (ii) $(a^m)^n=a^{mn}$ (iii) $(ab)^n = a^nb^n$ Use rule (i) above to obtain: $=\dfrac{(2x^3)^2}{5^2} \\=\dfrac{(2x^3)^2}{5(5)} \\=\dfrac{(2x^3)^2}{25}$ Use rule (iii) above to obtain: $=\dfrac{2^2(x^3)^2}{25} \\=\dfrac{4(x^3)^2}{25}$ Use rule (ii) above to obtain: $=\dfrac{4x^{3(2)}}{25} \\=\dfrac{4x^6}{25}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.