## Introductory Algebra for College Students (7th Edition)

$\dfrac{4x^6}{25}$
RECALL: (i) $\left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}, b\ne0$ (ii) $(a^m)^n=a^{mn}$ (iii) $(ab)^n = a^nb^n$ Use rule (i) above to obtain: $=\dfrac{(2x^3)^2}{5^2} \\=\dfrac{(2x^3)^2}{5(5)} \\=\dfrac{(2x^3)^2}{25}$ Use rule (iii) above to obtain: $=\dfrac{2^2(x^3)^2}{25} \\=\dfrac{4(x^3)^2}{25}$ Use rule (ii) above to obtain: $=\dfrac{4x^{3(2)}}{25} \\=\dfrac{4x^6}{25}$