Answer
$\frac{9}{7}y^8$
Work Step by Step
Divide the monomials by cancelling out common factors of the numbers and subtracting the exponents of variables.
$\frac{9y^{19}}{7y^{11}}=\frac{9}{7}y^{(19-11)}=\frac{9}{7}y^{8}$
Check the answer.
$7y^{11}(\frac{9}{7}y^{8})=\frac{7(9)}{7}y^{(11+8)}=9y^{19}$
