Answer
$\frac{7}{5}y^{12}$
Work Step by Step
Divide the monomials by cancelling out common factors of the numbers and subtracting the exponents of variables.
$\frac{7y^{17}}{5y^5}=\frac{7}{5}y^{(17-5)}=\frac{7}{5}y^{12}$
Check the answer.
$5y^5(\frac{7}{5}y^{12})=\frac{5(7)}{5}y^{(5+12)}=7y^{17}$
