## Introductory Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 3 - Section 3.5 - The Point-Slope Form of the Equation of a Line - Exercise Set - Page 261: 9

#### Answer

y+2=-1(x+$\frac{1}{2}$) y=-x-$\frac{5}{2}$

#### Work Step by Step

y-y$_1$=m(x-x$_1$) y-(-2)=-1(x-(-$\frac{1}{2}$)) y+2=-1(x+$\frac{1}{2}$) This is point-slope form. Now, isolate y to find slope-intercept form. y+2=-1(x)-1($\frac{1}{2}$) y+2=-x-$\frac{1}{2}$ y+2-2=-x-$\frac{1}{2}$-2 y=-x-$\frac{1}{2}$-$\frac{4}{2}$ y=-x-$\frac{5}{2}$ This is slope-intercept form.

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