# Chapter 3 - Section 3.5 - The Point-Slope Form of the Equation of a Line - Exercise Set - Page 261: 13

y+2=-$\frac{2}{3}$(x-6) y=-$\frac{2}{3}$x+2

#### Work Step by Step

y-y$_1$=m(x-x$_1$) y-(-2)=-$\frac{2}{3}$(x-6) y+2=-$\frac{2}{3}$(x)-$\frac{2}{3}$(-6) This is point-slope form. Now isolate y to find slope-intercept form. y+2=-$\frac{2}{3}$x+$\frac{12}{3}$ y+2=-$\frac{2}{3}$+4 y+2-2=-$\frac{2}{3}$x+4-2 y=-$\frac{2}{3}$x+2 This is slope=intercept form.

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