Introductory Algebra for College Students (7th Edition)

Published by Pearson

Chapter 3 - Section 3.5 - The Point-Slope Form of the Equation of a Line - Exercise Set - Page 261: 8

Answer

y+3=-11(x-0) y=-11x-3

Work Step by Step

y-y$_1$=m(x-x$_1$) y-(-3)=-11(x-0) y+3=-11(x-0) This is point-slope form. Now isolate y to find slope-intercept form. y+3=-11(x)-11(0) y+3=-11x y+3-3=-11x-3 y=-11x-3 This is slope-intercept form.

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