## Introductory Algebra for College Students (7th Edition)

y-0=$\frac{1}{2}$(x-4) y=$\frac{1}{2}$x-2
If the x-intercept is 4, then the line contains the point (4,0). If the y-intercept, represented by the letter b, is -2, then the line contains the point (0,-2). m=$\frac{y_2-y_1}{x_2-x_1}$ m=$\frac{-2-0}{0-4}$ m=$\frac{-2}{-4}$ m=$\frac{1}{2}$ y-y$_1$=m(x-x$_1$) y-0=$\frac{1}{2}$(x-4) This is point-slope form. y=mx+b y=$\frac{1}{2}$x+(-2) y=$\frac{1}{2}$x-2 This is slope-intercept form.