Answer
y-0=-$\frac{2}{3}$(x+1)
y=-$\frac{3}{2}$x-$\frac{3}{2}$
Work Step by Step
If the x-intercept is -1, then the line contains the point (-1,0).
m=$\frac{y_2-y_1}{x_2-x_1}$
m=$\frac{-3-0}{1+1}$
m=$\frac{-3}{2}$
m=-$\frac{3}{2}$
y-y$_1$=m(x-x$_1$)
y-0=-$\frac{3}{2}$(x-(-1))
y-0=-$\frac{3}{2}$(x+1)
This is point-slope form.
y=-$\frac{3}{2}$(x+1)
y=-$\frac{3}{2}$(x)-$\frac{3}{2}$(1)
y=-$\frac{3}{2}$x-$\frac{3}{2}$
This is slope-intercept form.