Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.3 - Solving Linear Equations - Exercise Set - Page 141: 22



Work Step by Step

8(y+3)=3(2y+12) 8y+8(3)=3(2y)+3(12) 8y+24=6y+36 8y-6y+24=36 2y+24=36 2y=36-24 2y=12 2y$\div$2=12$\div$2 y=6 Check the answer. 8(6+3)=3(2(6)+12) 8(9)=3(12+12) 72=3(24) 72=72
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