Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.3 - Solving Linear Equations - Exercise Set - Page 141: 20



Work Step by Step

$3(3x-1)=4(3+3x)$ $3(3x)-3(1)=4(3)+4(3x)$ $9x-3=12+12x$ $9x-12x-3=12$ $-3x-3=12$ $-3x=12+3$ $-3x=15$ $-3x\div(-3)=15\div(-3)$ $x=-5$ Check the answer. 3(3(-5)-1)=4(3+3(-5)) 3(-15-1)=4(3-15) 3(-16)=4(-12) -48=-48
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