## Introductory Algebra for College Students (7th Edition)

$z=9$
$3(3z+5)-7=89$ $3(3z+5)=89+7$ $3(3z+5)=96$ $9z+15=96$ $9z=96-15$ $9z=81$ $\frac{9z}{9}=\frac{81}{9}$ $z=9$ Check the answer. 3(3(9)+5)-7=89 3(27+5)-7=89 3(32)-7=89 96-7=89 89=89