Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.3 - Solving Linear Equations - Exercise Set - Page 141: 14



Work Step by Step

$3(3z+5)-7=89$ $3(3z+5)=89+7$ $3(3z+5)=96$ $9z+15=96$ $9z=96-15$ $9z=81$ $\frac{9z}{9}=\frac{81}{9}$ $z=9$ Check the answer. 3(3(9)+5)-7=89 3(27+5)-7=89 3(32)-7=89 96-7=89 89=89
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