Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.3 - Solving Linear Equations - Exercise Set - Page 141: 21



Work Step by Step

$8(y+2)=2(3y+4)$ $8(y)+8(2)=2(3y)+2(4)$ $8y+16=6y+8$ $8y-6y+16=8$ $2y+16=8$ $2y=8-16$ $2y=-8$ $y=\frac{-8}{2}$ $y=-4$ Check the answer. 8(-4+2)=2(3(-4)+4) 8(-2)=2(-12+4) -16=2(-8) -16=-16
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