Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.3 - Solving Linear Equations - Exercise Set - Page 141: 10



Work Step by Step

$4(2x-3)=32$ $\frac{4(2x-3)}{4}=\frac{32}{4}$ $2x-3=8$ $2x=8+3$ $2x=11$ $x=\frac{11}{2}$ Check the answer. 4(2($\frac{11}{2}$)-3)=32 4(11-3)=32 4(8)=32 32=32
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