## Intermediate Algebra for College Students (7th Edition)

$x=-\frac{1}{2}$
When the properties of exponents are used, $\dfrac{1}{\sqrt3} = 3^{-\frac{1}{2}}$. Thus, the given expression is equivalent to $\log_3{(3^{-\frac{1}{2}})}$ Let $\log_{3}{(3^{-\frac{1}{2}})} = x$ RECALL: $\log_b{y} =x \longrightarrow b^x=y$ Use the rule above, where $y=3^{-\frac{1}{2}}$ and $b=3$, to obtain: $3^x=3^{-\frac{1}{2}}$ Use the rule "If $a^x=a^y$, then $x=y$" to obtain: $x=-\frac{1}{2}$