Answer
$x=2$
Work Step by Step
First, we let
$\log_{7}{49} = x$
RECALL:
$\log_b{y} =x \longrightarrow b^x=y$
Use the rule above, where y=49 and b=7, to obtain:
$7^x=49$
Write 49 as $ 7^2$ to obtain:
$7^x=7^2$
Use the rule "If $a^x=a^y$, then $x=y$" to obtain:
$x=2$
