## Intermediate Algebra for College Students (7th Edition)

$=2$
First, we let $\log_{4}{16} = x$ RECALL: $\log_b{y} =x \longrightarrow b^x=y$ Use the rule above, where y=16 and b=4, to obtain: $4^x=16$ Write 16 as $4^2$ to obtain: $4^x=4^2$ Use the rule "If $a^x=a^y$, then $x=y$" to obtain: $x=2$