## Intermediate Algebra for College Students (7th Edition)

$\log_2{\frac{1}{16}}=-4$
RECALL: $a^x=y \longrightarrow \log_{a}{y}=x$ Use the rule above, with $a=2$, $x= -4$, and $y=\frac{1}{16}$, to obtain: $\log_2{\frac{1}{16}}=-4$