Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.3 - Logarithmic Functions - Exercise Set: 11

Answer

$\log_2{\frac{1}{16}}=-4$

Work Step by Step

RECALL: $a^x=y \longrightarrow \log_{a}{y}=x$ Use the rule above, with $a=2$, $x= -4$, and $y=\frac{1}{16}$, to obtain: $\log_2{\frac{1}{16}}=-4$
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