Answer
$\log_2{\frac{1}{16}}=-4$
Work Step by Step
RECALL:
$a^x=y \longrightarrow \log_{a}{y}=x$
Use the rule above, with $a=2$, $x= -4$, and $y=\frac{1}{16}$, to obtain:
$\log_2{\frac{1}{16}}=-4$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 9 - Section 9.3 - Logarithmic Functions - Exercise Set - Page 700: 11
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