Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.3 - Logarithmic Functions - Exercise Set - Page 700: 28



Work Step by Step

First, we let $\log_{3}{\frac{1}{9}} = x$ RECALL: $\log_b{y} =x \longrightarrow b^x=y$ Use the rule above, where $y=\frac{1}{9}$ and $b=3$, to obtain: $3^x=\frac{1}{9}$ Write $\frac{1}{9}$ as $ 3^{-2}$ to obtain: $3^x=3^{-2}$ Use the rule "If $a^x=a^y$, then $x=y$" to obtain: $x=-2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.