Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.4 - Equations Quadratic in Form - Exercise Set - Page 637: 76


$\dfrac{-x-5}{x+3}$ or, $-\dfrac{(x+5)}{x+3}$

Work Step by Step

Given: $\dfrac{x+1}{x+3}-2$ Solve the given expression as follows: $\dfrac{x+1}{x+3}-2=\dfrac{x+1-2(x+3)}{x+3}$ or,$=\dfrac{x+1-2x-6}{x+3}$ Hence, $=\dfrac{-x-5}{x+3}$ or, $=-\dfrac{(x+5)}{x+3}$
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