## Intermediate Algebra for College Students (7th Edition)

$\dfrac{-x-5}{x+3}$ or, $-\dfrac{(x+5)}{x+3}$
Given: $\dfrac{x+1}{x+3}-2$ Solve the given expression as follows: $\dfrac{x+1}{x+3}-2=\dfrac{x+1-2(x+3)}{x+3}$ or,$=\dfrac{x+1-2x-6}{x+3}$ Hence, $=\dfrac{-x-5}{x+3}$ or, $=-\dfrac{(x+5)}{x+3}$