Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.4 - Equations Quadratic in Form - Exercise Set - Page 637: 75



Work Step by Step

Given: $x^3+x^2=4x+4$ Solve the given expression as follows: $x^3+x^2-4x-4=0$ or, $x^2(x+1)-4(x+1)=0$ or, $(x+1)(x^2-4)=0$ or, $(x+1)(x-2)(x+2)=0$ or, $x=-1,-2,2$ Our solution set is: {$-2,-1,2$}
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