Answer
$\dfrac{1+3i}{2}$
Work Step by Step
Given: $\dfrac{2+i}{1-i}$
Solve the given expression as follows:
$\dfrac{2+i}{1-i}=\dfrac{2+i}{1-i} \times \dfrac{1+i}{1+i}$
or, $=\dfrac{2+2i+i^2+i}{1^2-i^2}$
or, $=\dfrac{2+2i-1+i}{1+1}$
or, $=\dfrac{1+3i}{2}$
