Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.4 - Equations Quadratic in Form - Exercise Set - Page 637: 61

Answer

Makes sense. An equation that is quadratic in form $au^2 + bu + c = 0$ is one that has been expressed as a quadratic equation by letting $u$ be equal to the variable factor that reappears squared. However, getting the values of $u$ is not the end of the solution because in quadratic equations, what is asked is to solve for $x$. For example: Given the equation, $x^4 - 8x^2 - 9 = 0$, it can be rewritten as: $u^2 - 8u - 9 = 0$ by letting $u=x^2$. Solving for $u$ will give values of $9$ and $-1$. The original substitution, $u = x^2$ is then used to solve for $x$. Thus, $x^2 = 9$ $x = ±3$ $x^2 = -1$ $x=±i$

Work Step by Step

Makes sense. An equation that is quadratic in form $au^2 + bu + c = 0$ is one that has been expressed as a quadratic equation by letting $u$ be equal to the variable factor that reappears squared. However, getting the values of $u$ is not the end of the solution because in quadratic equations, what is asked is to solve for $x$. For example: Given the equation, $x^4 - 8x^2 - 9 = 0$, it can be rewritten as: $u^2 - 8u - 9 = 0$ by letting $u=x^2$. Solving for $u$ will give values of $9$ and $-1$. The original substitution, $u = x^2$ is then used to solve for $x$. Thus, $x^2 = 9$ $x = ±3$ $x^2 = -1$ $x=±i$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.