Answer
$\dfrac{1}{(5x-1)}$
Work Step by Step
Given: $\dfrac{2x^2}{10x^3-2x^2}$
Solve the given expression as follows:
$\dfrac{2x^2}{10x^3-2x^2}=\dfrac{2x^2}{2x^2(5x-1)}$
or,
$\dfrac{2x^2}{10x^3-2x^2}=\dfrac{2x^2}{2x^2(5x-1)}=\dfrac{1}{(5x-1)}$
Hence, $\dfrac{2x^2}{10x^3-2x^2}=\dfrac{1}{(5x-1)}$
