Answer
$\dfrac{y^{12}}{x^8}$ or, $x^{-8}y^{12}$
Work Step by Step
Simplify. $(x^{-2}y^3)^4$
Now, $(x^{-2}y^3)^4=(x^{-2})^4 \cdot (y^3)^4$
or, $=x^{-8}y^{12}$
Hence,
$=\dfrac{y^{12}}{x^8}$ or, $x^{-8}y^{12}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.1 - Radical Expressions and Functions - Exercise Set - Page 514: 137
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