Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.1 - Radical Expressions and Functions - Exercise Set - Page 514: 137


$\dfrac{y^{12}}{x^8}$ or, $x^{-8}y^{12}$

Work Step by Step

Simplify. $(x^{-2}y^3)^4$ Now, $(x^{-2}y^3)^4=(x^{-2})^4 \cdot (y^3)^4$ or, $=x^{-8}y^{12}$ Hence, $=\dfrac{y^{12}}{x^8}$ or, $x^{-8}y^{12}$
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