Answer
$\dfrac{2}{x^3}$ or, $2 x^{-3}$
Work Step by Step
Simplify. $\dfrac{32x^2}{16x^5}$
Now, $\dfrac{32x^2}{16x^5}=2 x^{2-5}$
or, $=2 x^{-3}$
Hence,
$=\dfrac{2}{x^3}$ or, $2 x^{-3}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.1 - Radical Expressions and Functions - Exercise Set - Page 514: 136
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
