Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.1 - Radical Expressions and Functions - Exercise Set - Page 514: 135

Answer

$\dfrac{128}{x}$

Work Step by Step

Simplify. $(2^3 x^5)(2^4x^{-6})$ Now, $(2^3 x^5)(2^4x^{-6})=2^{3+4}x^{5-6}$ or, $=2^7 x^{-1}$ Hence, $=\dfrac{128}{x}$
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