Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.1 - Radical Expressions and Functions - Exercise Set - Page 514: 132

Answer

$7x+30$

Work Step by Step

Simplify. $(3x-2)[x-3(x+5)]$ Now, $(3x-2)[x-3(x+5)]=3x-2[x-3x-15]$ This implies $=3x-2[-2x-15]$ or, $=3x+4x+30$ Hence, $=7x+30$
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