Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.1 - Radical Expressions and Functions - Exercise Set - Page 514: 133

Answer

$\dfrac{x^8}{9y^6}$

Work Step by Step

Simplify. $(-3x^{-4}y^3)^{-2}$ Now, $(-3x^{-4}y^3)^{-2}=(-3)^{-2}(x^{-4})^{-2}(y^3)^{-2}$ or, $=(-3)^{-2}x^8y^{-6}$ or, $=\dfrac{x^8}{9y^6}$
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