Answer
$\dfrac{x^8}{9y^6}$
Work Step by Step
Simplify. $(-3x^{-4}y^3)^{-2}$
Now, $(-3x^{-4}y^3)^{-2}=(-3)^{-2}(x^{-4})^{-2}(y^3)^{-2}$
or, $=(-3)^{-2}x^8y^{-6}$
or, $=\dfrac{x^8}{9y^6}$
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