Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Test - Page 499: 27

Answer

$45$ foot-candles

Work Step by Step

Step 1:- Translate the statement to form an equation. Let the intensity of the light be $I$. and the distance from the source be $D$. $\Rightarrow I=\frac{k}{D^2}$ ...... (1) Step 2:- Substitute the first set of values into equation (1) to find the value of $k$. The given values are $I=20$ foot-candles and $D=15$ feet. Substitute into equation (1). $\Rightarrow 20=\frac{k}{15^2}$ $\Rightarrow 20=\frac{k}{225}$ Multiply both sides by $225$. $\Rightarrow 225\cdot 20=225\cdot \frac{k}{225}$ Simplify. $\Rightarrow 4500=k$ Step 3:- Substitute the value of $k$ into the original equation. Substitute $k=4500$ into equation (1). $\Rightarrow I=\frac{4500}{D^2}$ ...... (2) Step 4:- Solve the equation to find the required value. Substitute $D=10$ feet into equation (2). $\Rightarrow I=\frac{4500}{10^2}$ Simplify. $\Rightarrow I=\frac{4500}{100}$ $\Rightarrow I=45$ Hence, the intensity of the light is $45$ foot-candles.
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