Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Test - Page 499: 25

Answer

$12$ hours.

Work Step by Step

Time taken by first pipe to fill the pool: $3$ hours. Fraction of the pool filled in one hour $=\frac{1}{3}$. Time taken by second pipe to empty the pool: $4$ hours. Fraction of the pool emptied in one hour $=\frac{1}{4}$. Let's note by $t$ the time it takes to fill the pool under the given conditions. Fraction of the pool filled in one hour $=\frac{1}{t}$ The equation modelling the given conditions: $\Rightarrow \frac{1}{3}-\frac{1}{4}=\frac{1}{t}$ The LCD is $12t$ Multiply both side by LCD to clear fractions. $\Rightarrow 12t\left (\frac{1}{3}-\frac{1}{4}\right)=12t\left (\frac{1}{t}\right)$ Use the distributive property. $\Rightarrow 12t\left (\frac{1}{3}\right)-12t\left (\frac{1}{4}\right)=12t\left (\frac{1}{t}\right)$ Simplify. $\Rightarrow 4t-3t=12$ $\Rightarrow t=12$ Hence, it will take $12$ hours to fill the pool.
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