Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Test - Page 499: 26

Answer

$4$ miles per hour.

Work Step by Step

Average speed of the motorboat in still water is $20$ miles per hour. Let the speed of the current be $x$. Speed of the motorboat against the current $20-x$. Speed of the motorboat with the current $20+x$. Formula for the time is $=\frac{Distance}{Speed}$. The given condition is $\Rightarrow \frac{3}{20+x}=\frac{2}{20-x}$ The LCD is $(20+x)(20-x)$. Multiply the equation by LCD to clear fractions. $\Rightarrow (20+x)(20-x)\left (\frac{3}{20+x}\right )=(20+x)(20-x)\left (\frac{2}{20-x}\right )$ Cancel common factors. $\Rightarrow 3(20-x)=2(20+x)$ Use distributive property. $\Rightarrow 60-3x=40+2x$ Add $3x-40$ to both sides. $\Rightarrow 60-3x+3x-40=40+2x+3x-40$ Add like terms. $\Rightarrow 20=5x$ Divide both sides by $5$. $\Rightarrow \frac{20}{5}=\frac{5x}{5}$ Simplify. $\Rightarrow 4=x$ Hence, the current's rate is $4$ miles per hour. Note: Check if the solution is correct. The equation is defined for all real values of $x$ except the zeros of the denominators, which are $-20$ and $20$. Since our solution is different than those values, it is correct.
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