Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.8 - Modeling Using Variation - Exercise Set - Page 487: 9



Work Step by Step

The equation here is $y=\frac{kab}{\sqrt c}$. Thus $12=\frac{2\cdot3k}{\sqrt{25}}\\12=\frac{6}{5}k\\k=10$. Hence $y=\frac{10ab}{\sqrt c}=\frac{10\cdot5\cdot3}{\sqrt 9}=50.$
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