Answer
$50$
Work Step by Step
The equation here is $y=\frac{kab}{\sqrt c}$. Thus $12=\frac{2\cdot3k}{\sqrt{25}}\\12=\frac{6}{5}k\\k=10$.
Hence $y=\frac{10ab}{\sqrt c}=\frac{10\cdot5\cdot3}{\sqrt 9}=50.$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Section 6.8 - Modeling Using Variation - Exercise Set - Page 487: 9
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