Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.8 - Modeling Using Variation - Exercise Set - Page 487: 8



Work Step by Step

The equation here is $C=kAT$. Thus $175=2100\cdot4k\\175=8400k\\k=\frac{1}{48}$. Hence $y=\frac{1}{48}AT=\frac{1}{48}\cdot2400\cdot6=300.$
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