Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.8 - Modeling Using Variation - Exercise Set - Page 487: 10

Answer

$216$.

Work Step by Step

Translate the question $\Rightarrow y=k\cdot\frac{mn^2}{p}$ Substitute $y=15,m=2,n=1$ and $p=6$ into the equation. $\Rightarrow 15=k\cdot\frac{(2)(1)^2}{6}$ Simplify. $\Rightarrow 15=k\cdot\frac{2}{6}$ $\Rightarrow 15=k\cdot\frac{1}{3}$ Multiply both sides by $3$. $\Rightarrow 15\cdot 3=3k\cdot\frac{1}{3}$ Simplify. $\Rightarrow 45=k$ Now substitute $k=45,m=3,n=4$ and $p=10$ into the equation. $\Rightarrow y=45\cdot\frac{(3)(4)^2}{10}$ Simplify. $\Rightarrow y=45\cdot\frac{48}{10}$ $\Rightarrow y=216$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.